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We can avoid this in two ways. Firstly, we can declare that any code that observes two nodes must depend on those nodes, and then apply the topological sort we described earlier. Alternatively, we can declare that any code that might be able to observe two nodes can only be run after all nodes have finished running2. These both work, but again they require us to be able to observe the full dependency tree and topologically sort all nodes.
。新收录的资料对此有专业解读
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2026-03-10 00:00:00:03014442510http://paper.people.com.cn/rmrb/pc/content/202603/10/content_30144425.htmlhttp://paper.people.com.cn/rmrb/pad/content/202603/10/content_30144425.html11921 中国平煤神马集团 向新图强 活力焕新
I am now working on [problem] and believe [your work] would help.，详情可参考新收录的资料